Algebraic geometry II - schemes and sheaves
MATH-510
Solution - Hand in 4
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Description
It seems that you guys were not very loquacious in showing that the module was free - I agree that is kinda immediate but this also was one of the only thing asked for the exercise. An 
-module 
is free of rank 2 if there is an isomorphism
Some of you have disregarded to show injectivity.
So you can check the solution for an argument. You may have lost a point or half a point for this reason.
-module is free of rank 2 if there is an isomorphismSome of you have disregarded to show injectivity.
So you can check the solution for an argument. You may have lost a point or half a point for this reason.