Common Source Amplifier Design

Christian Enz

Swiss Federal Institute of Technology (EPFL), Lausanne, Switzerland

Introduction¶

This notebook presents the design of a simple common-source transistor for various specifications. The objective is to make the student more familiar to the concept of inversion coefficient $IC$ and the $G_m/I_D$ design methodology.

To run the simulation you first need to install Smash on your computer. Please follow the instructions given in the Moodle site.

Technology parameters¶

We will use the parameters given below that correspond to a generic 180nm bulk CMOS process.

Main physical parameters:
═════════════════════════
$T =$ 300 K
$U_T =$ 25.875 mV
Main process parameters for TSMC 0.18um:
════════════════════════════════════════
$V_{DD} =$ 1.8 V
$C_{ox} =$ 8.443 $\frac{{fF}}{{\mu m^2}}$
$W_{min} =$ 200 nm
$L_{min} =$ 180 nm
nNMOS parameters:
═════════════════
Long-channel sEKV parameters:
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$n =$ 1.27
$I_{spec\Box} =$ 715 nA
$V_{T0} =$ 455 mV
$L_{sat} =$ 26 nm
$\lambda =$ 20 $\frac{{V}}{{\mu m}}$
Overlap capacitances:
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$C_{GDo} =$ 0.366 $\frac{{fF}}{{\mu m}}$
$C_{GSo} =$ 0.366 $\frac{{fF}}{{\mu m}}$
$C_{GBo} =$ 0.000 $\frac{{fF}}{{\mu m}}$
Junction capacitances:
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$C_J =$ 1.000 $\frac{{fF}}{{\mu m^2}}$
$C_{JSW} =$ 0.200 $\frac{{fF}}{{\mu m}}$
1/f noise parameters:
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$K_F =$ 8.1e-24 J
$AF =$ 1.0
$\rho =$ 5.794e-02 $\frac{{V \cdot m^2}}{{A \cdot s}}$
Matching parameters:
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$A_{VT} =$ 5 $mV \cdot \mu m$
$A_{\beta} =$ 1 $\% \cdot \mu m$
Source and drain sheet resistance:
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$R_{sh} =$ 600 $\frac{\Omega}{\mu m}$
Channel width and length corrections
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
$\Delta W =$ 39 nm
$\Delta L =$ −76 nm

Problem 1: Imposing the gain-bandwidth product (unity gain frequency)¶

Schematic of the common-source (CS) loaded by capacitor $C_L$.

In this first example we will design the CS shown in the above figure for the specifications at room temperature given below by imposing the inversions coefficient and the load capacitance:

Analysis¶

Small-signal schematic of the common-source (CS).

The small-signal schematic of the CS amplifier is shown in the above figure. The transfer function is given by

\begin{equation*} H(s) \triangleq \frac{\Delta V_{out}}{\Delta V_{in}} = \frac{A_{dc}}{1+\frac{s}{\omega_c}}, \end{equation*}

where $A_{dc} = -G_m/G_{ds}$ is the dc gain and $\omega_c = G_{ds}/C_L$ the cut-off frequency.

The magnitude of the frequency response is then given by

\begin{equation*} |H(\omega)| = \frac{|A_{dc}|}{\sqrt{1+\left(\frac{\omega}{\omega_c}\right)^2}} \cong \frac{\omega_u}{\omega} \end{equation*}

for $\omega_c \ll \omega$ where

\begin{equation*} \omega_u = |A_{dc}| \cdot \omega_c = \frac{G_m}{C_L} \end{equation*}

is the unity-gain frequency or gain-bandwidth product.

Specifications¶

The specifications for Problem 1 are given below.

$f_u =$ 100 MHz
$IC =$ 1
$C_L =$ 1 pF

Long-channel case¶

Design¶

For the long-channel case, we take:

$L = $ 1 µm
$L_{eff} = $ 924 nm

We can calculate the required transconductance $G_m$ from the GBW product and the constant load capacitance as

$G_m = $ 628.319 µA/V

Assuming a long-channel transistor we can neglect the effect of velocity saturation and calculate the current efficiency for the chosen inversion coefficient as

$\frac{G_m\,n U_T}{I_D} = $ 0.618

By definition of the current efficiency we can get the corresponding bias current

$I_b = $ 33.444 µA

From the bias current and the inversion coefficient we get the specific current as

$I_{spec} = $ 33.444 µA

The W/L is the simply given by

$\frac{W_{eff}}{L_{eff}} =$ 46.774

From which we get the effective and drawn width

$W_{eff} = $ 43.220 µm
$W = $ 43.180 µm

We can check what is the resulting dc gain by estimating the output conductance

$G_{ds} = $ 1.672 µA/V
$A_{dc} = $ −376
$A_{dc,dB} = $ 51 dB

We also calculate the area and perimeter of the drain to estimate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 35 fF
$C_{GD} =$ 16 fF
$C_D =$ 51 fF
$C_{L0} =$ 949 fF

Simulations¶

Schematic of the common-source (CS) gain stage used for simulation.

We can now check whether we get the correct GBW and DC gain using Smash simulations with the schematic shown in the above figure, where transistor $M_2$ is used to correctly bias the gate of the CS transistor $M_1$ for the desired bias current $I_b$. Notice that transistor $M_2$ has been made noiseless so that we only get the noise of $M_1$.

The simulations will be performed with the following parameters.

.param VDD=1.8 Ib=33.44u
.param CL=949f
.param W=43.18u L=1u AD=1.73e-11 PD=8.72e-05
.param fdec=101 fmin=1k fmax=1G
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  6.688e-05 on VDD
Iteration    2, residual  1.439e-03 on M2::DI
Iteration    3, residual  8.343e-04 on M1::DI
Iteration    4, residual  4.424e-04 on M1::DI
Iteration    5, residual  2.113e-04 on M1::DI
Iteration    6, residual  8.880e-05 on M1::DI
Iteration    7, residual  3.090e-05 on M2::DI
Iteration    8, residual  7.432e-06 on M2::DI
Iteration    9, residual  7.420e-07 on M2::DI
Iteration   10, residual  9.422e-09 on M2::DI
Iteration   11, residual  1.576e-12 on M1::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 250ms 
Elapsed Time: 6s 903ms 945us

Adc = 51.632 dB
GBW = 9.758e+01 MHz
Dominant pole fp1 = 255.230 kHz

The simulated GBW and DC gain almost match the target specs.

Short-channel case (including velocity saturation)¶

Design¶

For the short-channel case we will use the shortest channel length for this technology, namely:

$L = $ 180 nm
$L_{eff} = $ 104 nm

The velocity parameter for the chosen length is then given by

$\lambda_c =$ 0.250

The procedure is then the same: we first get the bias current from the current efficiency but including the effect of velocity saturation

$\frac{G_m\,n U_T}{I_D} = $ 0.587

We see that the current efficiency $G_m n U_T/I_D$ is slightly smaller than for the long-channel case due to velocity saturation.

The bias current is then given by

$I_b = $ 35.185 µA

Despite we use a shorter channel-length, the required bias current is about the same than the one from the long-channel case. This is due to velocity saturation which reduces the current efficiency even at $IC=1$.

From the bias current and the inversion coefficient we get the specific current as

$I_{spec} = $ 35.185 µA

The W/L is the simply given by

$\frac{W_{eff}}{L_{eff}} =$ 49.209

From which we get the effective and drawn width

$W_{eff} = $ 5.118 µm
$W = $ 5.080 µm

We can check what is the resulting dc gain by estimating the output conductance

$G_{ds} = $ 16.916 µA/V
$A_{dc} = $ −37
$A_{dc,dB} = $ 31 dB

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 4.224 fF
$C_{GD} =$ 1.862 fF
$C_D =$ 6.086 fF
$C_{L0} =$ 993.914 fF

Simulations¶

We can check whether we get the correct GBW and dc gain using Smash simulations with the following values of the parameters:

.param VDD=1.8 Ib=35.18u
.param CL=994f
.param W=5.08u L=0.18u AD=2.03e-12 PD=1.10e-05
.param fdec=101 fmin=1k fmax=1G
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  7.036e-05 on VDD
Iteration    2, residual  9.759e-04 on M2::DI
Iteration    3, residual  5.837e-04 on M2::DI
Iteration    4, residual  3.139e-04 on M2::DI
Iteration    5, residual  1.484e-04 on M2::DI
Iteration    6, residual  5.880e-05 on M2::DI
Iteration    7, residual  1.751e-05 on M2::DI
Iteration    8, residual  2.877e-06 on M2::DI
Iteration    9, residual  1.141e-07 on M2::DI
Iteration   10, residual  1.983e-10 on M2::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 125ms 
Elapsed Time: 6s 193ms 675us

Adc = 32.199 dB
GBW = 9.521e+01 MHz
Dominant pole fp1 = 2337.800 kHz

The DC gain is above specs, however the GBW is slightly below specs. This would require some additional fine tuning.

Problem 2: Imposing the power consumption¶

Specifications¶

We now impose the power consumption, the inversion coefficient and the load capacitance:

$P =$ 100 µW
$IC =$ 1
$C_L =$ 1 pF

Long-channel case¶

Design¶

For the long-channel case, we have:

$L = $ 1 µm
$L_{eff} = $ 924 nm

The maximum available current is directly given by

$I_b = $ 55.6 µA

Since the inversion coefficient is chosen we get the specific current as

$I_{spec} = $ 55.6 µA

The normalized transconductance is the given by the chosen inversion coefficient

$\frac{G_m\,n U_T}{I_D} = $ 0.587

From which we derive the transconductance and the gain-bandwidth product for the load capacitance

$G_m = $ 1.044 mA/V
$f_u =$ 166.116 MHz

The W/L is then obtained from

$\frac{W_{eff}}{L_{eff}} =$ 77.700

and finally the effective width and drawn width are given by

$W_{eff} = $ 71.794 µm
$W = $ 71.760 µm

We can calculate the dc gain by first estimating the output conductance

$G_{ds} = $ 3.006 µA/V
$A_{dc} = $ −347
$A_{dc,dB} = $ 51 dB

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 58 fF
$C_{GD} =$ 26 fF
$C_D =$ 84 fF
$C_{L0} =$ 916 fF

Simulations¶

We can check whether we get the correct GBW and dc gain using Smash simulations with the following values of the parameters:

.param VDD=1.8 Ib=55.56u
.param CL=916f
.param W=71.76u L=1.00u AD=2.87e-11 PD=1.44e-04
.param fdec=101 fmin=1k fmax=1G
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  1.111e-04 on VDD
Iteration    2, residual  2.390e-03 on M2::DI
Iteration    3, residual  1.386e-03 on M1::DI
Iteration    4, residual  7.349e-04 on M1::DI
Iteration    5, residual  3.511e-04 on M1::DI
Iteration    6, residual  1.475e-04 on M1::DI
Iteration    7, residual  5.133e-05 on M2::DI
Iteration    8, residual  1.235e-05 on M2::DI
Iteration    9, residual  1.232e-06 on M2::DI
Iteration   10, residual  1.564e-08 on M2::DI
Iteration   11, residual  2.615e-12 on M1::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 156ms 250us
Elapsed Time: 6s 281ms 289us

Adc = 51.632 dB
GBW = 1.630e+02 MHz
Dominant pole fp1 = 424.970 kHz

The simulated GBW and DC gain are close to the theoretical results.

Short-channel case (including velocity saturation)¶

Design¶

For the short-channel case we will use the shortest channel length for this technology, namely:

$L = $ 180 nm
$L_{eff} =$ 104 nm

The procedure is basically the same except that we now need to account for velocity saturation.

$\lambda_c =$ 0.250
$g_{ms} =$ 0.587
$G_m = $ 992.099 µA/V
$f_u =$ 157.897 MHz

We see that the gain-bandwidth is now slightly smaller than what we obtained for the long-channel case. This illustrates the impact of velocity saturation which reduces the transconductance for a given current particularly in strong inversion. It will also have an impact on the dc gain since not only $G_m$ is smaller but $G_{ds}$ gets large because of the minimum channel length.

$\frac{W_{eff}}{L_{eff}} =$ 77.700
$W_{eff} = $ 8.081 µm
$W = $ 8.040 µm
$G_{ds} = $ 26.709 µA/V
$A_{dc} = $ −37
$A_{dc,dB} = $ 31 dB

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 6.6 fF
$C_{GD} =$ 2.9 fF
$C_D =$ 9.5 fF
$C_{L0} =$ 990.5 fF

Simulations¶

We can check whether we get the correct GBW and dc gain using LTspice simulations with the schematic given in Fig. \ref{fig:Problem1_long_schematic}.

The simulations will be performed for the following values of the parameters:

.param VDD=1.8 Ib=55.56u
.param CL=990f
.param W=8.04u L=0.18u AD=3.22e-12 PD=1.69e-05
.param fdec=101 fmin=1k fmax=1G
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  1.111e-04 on VDD
Iteration    2, residual  1.540e-03 on M2::DI
Iteration    3, residual  9.212e-04 on M2::DI
Iteration    4, residual  4.954e-04 on M2::DI
Iteration    5, residual  2.342e-04 on M2::DI
Iteration    6, residual  9.279e-05 on M2::DI
Iteration    7, residual  2.763e-05 on M2::DI
Iteration    8, residual  4.536e-06 on M2::DI
Iteration    9, residual  1.796e-07 on M2::DI
Iteration   10, residual  3.112e-10 on M2::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 187ms 500us
Elapsed Time: 6s 134ms 383us

Adc = 32.198 dB
GBW = 1.504e+02 MHz
Dominant pole fp1 = 3694.300 kHz

The simulated GBW and DC gain are close to the target specs.

Problem 3: Imposing the gain bandwidth product and the current budget¶

We now do not impose the inversion coefficient but the gain bandwidth product and the current budget. We keep the same load capacitance and consider a long channel.

Specifications¶

$f_u = GBW =$ 1 MHz
$I_b =$ 400 nA
$C_L =$ 1 pF
$L =$ 1 µm
$L_{eff} =$ 924 nm

Design¶

We first get the transconductance required to achieve the target gain-bandwidth product

$G_m =$ 6.283 µA/V

Knowing the bias current and the transconductance we can calculate the current efficiency as

$\frac{G_m\,n U_T}{I_D} =$ 0.517

from which we can derive the corresponding inversion coefficient by

$IC =$ 1.810

We see that we are in the moderate inversion region. The specific current is then given by

$I_{spec} = $ 221.0 nA

The W/L ratio is then obtained as

$\frac{W_{eff}}{L_{eff}} =$ 0.309

and finally the effective and drawn width

$W_{eff} = $ 286 nm
$W = $ 250 nm

The dc gain is directly estimated from the transconductance and the output conductance

$G_{ds} = $ 20.000 nA/V
$A_{dc} = $ −314
$A_{dc,dB} = $ 50 dB

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 360.0 aF
$C_{GD} =$ 91.6 aF
$C_D =$ 451.6 aF
$C_{L0} =$ 999.5 fF

We observe that the parasitic capacitance at the drain are negligible compared to the load capacitance.

Simulations¶

We can check whether we get the correct GBW and dc gain using the following values of the parameters:

.param VDD=1.8 Ib=400n
.param CL=1000f
.param W=0.25u L=1u AD=1.00e-13 PD=1.30e-06
.param fdec=101 fmin=10 fmax=10MEG
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  8.000e-07 on VDD
Iteration    2, residual  9.619e-06 on M2::DI
Iteration    3, residual  5.566e-06 on M1::DI
Iteration    4, residual  2.932e-06 on M1::DI
Iteration    5, residual  1.372e-06 on M1::DI
Iteration    6, residual  5.442e-07 on M1::DI
Iteration    7, residual  1.611e-07 on M2::DI
Iteration    8, residual  2.497e-08 on M2::DI
Iteration    9, residual  8.369e-10 on M2::DI
Iteration   10, residual  1.011e-12 on M2::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 
Elapsed Time: 6s 46ms 767us

Adc = 50.874 dB
GBW = 9.623e-01 MHz
Dominant pole fp1 = 2.752 kHz

The simulated GBW and DC gain are almost on specs.

Problem 4: Imposing the input-referred noise¶

Specifications¶

In this example, we impose the input-referred noise by setting the white noise and corner frequency.

$f_k = $ 100 kHz
$\sqrt{S_{nth}} =$ 30 $\frac{nV}{\sqrt{Hz}}$
$IC =$ 1
$C_L =$ 1 pF

Design¶

We need the flicker noise parameter $K_f$ and the oxide capacitance per unit area $C_{ox}$

$K_F =$ 8.1e-24 J
$C_{ox} =$ 8.443 $\frac{{fF}}{{\mu m^2}}$

Before deriving the transconductance is derived from the thermal noise specification we need to know the thermal noise excess factor for the given $IC$ (we assume long-channel case)

$\gamma_n =$ 0.717

The transconductance is then given by

$G_m =$ 13.186 µA/V

Once we have the transconductance, the procedure is similar to the previous one. Having imposed the inversion coefficient we can deduce the current efficiency factor as

$\frac{G_m\,n U_T}{I_D} =$ 0.618

By definition of the current efficiency we can get the corresponding bias current

$I_b =$ 701.84 nA

From the bias current and the inversion coefficient we get the specific current as

$I_{spec} = $ 701.84 nA

The W/L ratio is then obtained as

$\frac{W_{eff}}{L_{eff}} =$ 0.982

The corner frequency will actually set the flicker noise which is inversely proportional to the gate are. We can therefore calculate the gate area from the flicker noise remembering that the corner frequency is the frequency at which the flicker noise becomes equal to the white noise

$W \cdot L =$ 10.660 $\mu m^2$
$W_{eff} = $ 3.23 µm
$W = $ 3.20 µm
$L_{eff} = $ 3.30 µm
$L = $ 3.37 µm

Finally we can also calculate the gain-bandwidth product

$f_u =$ 2.099 MHz

The dc gain is directly estimated from the transconductance and the output conductance

$G_{ds} = $ 10.413 nA/V
$A_{dc} = $ −1.27 k
$A_{dc,dB} = $ 62.05 dB
$\sqrt{S_{nth}} =$ 30.000 $\frac{{nV}}{{\sqrt{{Hz}}}}$

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 3 fF
$C_{GD} =$ 1 fF
$C_D =$ 4 fF
$C_{L0} =$ 996 fF

Simulations¶

We can check whether we get the correct GBW and dc gain using the following values of the parameters:

.param VDD=1.8 Ib=0.70u
.param CL=996f
.param W=3.20u L=3.37u AD=1.28e-12 PD=7.20e-06
.param fdec=101 fmin=10 fmax=10MEG

We first can check the small-signal gain.

Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  1.400e-06 on VDD
Iteration    2, residual  3.480e-05 on M2::DI
Iteration    3, residual  2.031e-05 on M1::DI
Iteration    4, residual  1.091e-05 on M1::DI
Iteration    5, residual  5.323e-06 on M1::DI
Iteration    6, residual  2.308e-06 on M1::DI
Iteration    7, residual  8.482e-07 on M2::DI
Iteration    8, residual  2.299e-07 on M2::DI
Iteration    9, residual  3.074e-08 on M2::DI
Iteration   10, residual  7.572e-10 on M2::DI
Iteration   11, residual  4.899e-13 on M2::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 31ms 250us
Elapsed Time: 5s 999ms 686us

Adc = 62.501 dB
GBW = 2.043e+00 MHz
Dominant pole fp1 = 1.532 kHz

We can now check the input-referred noise.

Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  1.400e-06 on VDD
Iteration    2, residual  3.480e-05 on M2::DI
Iteration    3, residual  2.031e-05 on M1::DI
Iteration    4, residual  1.091e-05 on M1::DI
Iteration    5, residual  5.323e-06 on M1::DI
Iteration    6, residual  2.308e-06 on M1::DI
Iteration    7, residual  8.482e-07 on M2::DI
Iteration    8, residual  2.299e-07 on M2::DI
Iteration    9, residual  3.074e-08 on M2::DI
Iteration   10, residual  7.572e-10 on M2::DI
Iteration   11, residual  4.899e-13 on M2::DI


Operating point analysis completed (converged)
Noise
Noise analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 
Elapsed Time: 6s 31ms 638us

The simulated input-referred white noise and corner frequency are perfectly on target.

Problem 5: Minimum current for a given gain-bandwidth product¶

Schematic of the common-source (CS) illustrating the self-loading effect.

In this problem we want to find the minimum current required to achieve a given gain-bandwidth product accounting for the effect of self-loading as illustrated in the above figure.

Specifications¶

We will use the following specifications:

$f_u =$ 25 MHz
$C_L =$ 20 fF
$L = $ 1 µm
$L_{eff} = $ 924 nm

For accounting for the self-loading effect we need the capacitance per width $C_{DW}$

$C_p =$ 160.00 aF
$C_{L0} =$ 19.84 fF
$C_{DW} =$ 1.167 $\frac{{fF}}{{\mu m}}$

Design¶

We first calculate the various normalization parameters

$f_L =$ 174.4 MHz
$\Omega_n =$ 0.143
$f_w =$ 3.209 GHz
$\theta =$ 0.008
$IC_{opt} =$ 0.106
$i_{bopt} =$ 1.193
$AR_{opt} =$ 11.286
$\kappa =$ 18.407
$i_{bias,opt} =$ 0.171
$I_b =$ 122.3 nA
$\frac{W_{eff}}{L_{eff}} =$ 1.618
$W_{eff} = $ 1 µm
$W = $ 1 µm

The dc gain is directly estimated from the transconductance and the output conductance

$g_{ms} =$ 0.096
$I_{spec} =$ 1.157 µA
$G_m =$ 3.390 µA/V
$G_{ds} =$ 6.617 nA/V
$A_{dc} =$ 512.374
$A_{dc} =$ 54.2 dB

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 1.328 fF
$C_{GD} =$ 535.090 aF
$C_D =$ 1.863 fF
$C_{L0} =$ 18.137 fF

Simulations¶

We can check whether we get the correct GBW and DC gain using Smash simulations. The simulations will be performed for the following values of the parameters:

.param VDD=1.8 Ib=122n
.param CL=18.1f
.param W=1.46u L=1u AD=5.84e-13 PD=3.72e-06
.param fdec=101 fmin=1k fmax=100MEG
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  2.440e-07 on VDD
Iteration    2, residual  4.992e-05 on M2::DI
Iteration    3, residual  2.901e-05 on M2::DI
Iteration    4, residual  1.549e-05 on M2::DI
Iteration    5, residual  7.565e-06 on M2::DI
Iteration    6, residual  3.388e-06 on M2::DI
Iteration    7, residual  1.407e-06 on M2::DI
Iteration    8, residual  5.470e-07 on M2::DI
Iteration    9, residual  1.948e-07 on M2::DI
Iteration   10, residual  5.688e-08 on M2::DI
Iteration   11, residual  9.858e-09 on M2::DI
Iteration   12, residual  4.545e-10 on M2::DI
Iteration   13, residual  1.081e-12 on M2::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 203ms 125us
Elapsed Time: 6s 47ms 610us

Adc = 52.904 dB
GBW = 2.667e+01 MHz
Dominant pole fp1 = 60.295 kHz

The simulated GBW is slightly larger than specs and the DC gain is slightly lower than the theoretical result (it is not a spec in this problem).

Problem 6: Minimum current for a given gain-bandwidth product and dc gain¶

Specifications¶

In this problem we want to find the minimum current required to achieve a given gain-bandwidth product and a given dc gain accounting for the effect of self-loading. We will use the following specs:

$f_u =$ 25 MHz
$A_{dc,dB} = $ 40 dB
$C_{L0} =$ 20 fF

Design¶

We first calculate the various normalization parameters

$f_c =$ 250 kHz
$\xi =$ 1.387e-03
$IC_{opt} =$ 0.040
$I_{norm} =$ 103.347 nA
$g_{ms} =$ 0.039
$i_{bopt} =$ 1.079
$I_b =$ 111.496 nA
$w_{opt} =$ 27.893
$W_{norm} = $ 23.774 nm
$W_{eff} = $ 663.144 nm
$W = $ 620.000 nm
$l_{opt} =$ 1.039
$L_{norm} = $ 164 nm
$L_{eff} = $ 171 nm
$L = $ 250 nm

We also calculate the area and perimeter of the drain to calculate the junction capacitance and overlap capacitance in order to correct $C_L$ to get the correct $GBW$.

$C_{DBJ} =$ 656.000 aF
$C_{GD} =$ 227.230 aF
$C_D =$ 883.230 aF
$C_{L0} =$ 19.117 fF

Simulations¶

We can check whether we get the correct GBW and DC gain using Smash simulations.

.param VDD=1.8 Ib=111n
.param CL=19.1f
.param W=0.62u L=0.25u AD=2.48e-13 PD=2.04e-06
.param fdec=101 fmin=1k fmax=100MEG
Starting Smash simulation...

----------------------------------------------------------------------
-
- SMASH (TM) release 7.6.0 (64-bit) of Jun 30 2020
- Copyright (c) Dolphin Design, 1992-2020. All Rights Reserved.
-
----------------------------------------------------------------------

Output directory L:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash
Parsing circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Loading circuit l:\My Drive\Lectures\Master\Fundamentals of Analog VLSI Design\2024\Exercises\2024.10.16\Jupyter Notebook\Simulations\Smash\csamp.pat
Processing top-level
Elaborating circuit...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Elaborating circuit (logic)...
Elaborating circuit (creating devices)...
Elaborating circuit (elaborating devices)...
Initializing...
Searching for HZ nets: 0%
Linking analog resolution matrix...
Load completed.
Operating-Point analysis (trying logarithmic damping heuristics)...
Iteration    1, residual  2.220e-07 on VDD
Iteration    2, residual  8.405e-05 on M2::DI
Iteration    3, residual  4.947e-05 on M2::DI
Iteration    4, residual  2.644e-05 on M2::DI
Iteration    5, residual  1.272e-05 on M2::DI
Iteration    6, residual  5.544e-06 on M2::DI
Iteration    7, residual  2.259e-06 on M2::DI
Iteration    8, residual  8.869e-07 on M2::DI
Iteration    9, residual  3.343e-07 on M2::DI
Iteration   10, residual  1.136e-07 on M2::DI
Iteration   11, residual  2.910e-08 on M2::DI
Iteration   12, residual  3.536e-09 on M2::DI
Iteration   13, residual  7.007e-11 on M2::DI
Iteration   14, residual  2.886e-14 on M1::DI


Operating point analysis completed (converged)
Small Signal
Small signal analysis completed
Launch Measurements: 6
End Measurements

CPU Time:     5s 109ms 375us
Elapsed Time: 6s 206ms 579us

Adc = 38.339 dB
GBW = 2.559e+01 MHz
Dominant pole fp1 = 309.680 kHz

The simulated GBW is slightly above spec, whereas the simulated DC gain is slightly lower than spec.

Conclusion¶

This exercise has illustrated how to design (i.e. choose the bias current and the device size) a simple common-source amplifier using the inversion coefficient and the related functions for various specifications. It has been shown that a good fit to the specifications can be achieved in various modes of operation. It also has shown the limitation of the output conductance model which can only be used in a restricted region of operation. However it gives a first order result which can be further optimized by simulations.